Τι συμβαίνει εδώ?

Τι συμβαίνει εδώ?
Anonim

Απάντηση:

# | sin (x) | <= 1, "και" arctan (x) / x> = 0 #

Εξήγηση:

# "As" | sin (x) | <= 1 "και" arctan (x) / x> = 0, "έχουμε" #

# | (sin (1 / sqrt (x)) arctan (x)) / (x sqrt (ln (1 + x))) | <= | arctan (x) / (x sqrt (Ιη (1 + χ))) | #

(x) / (sqrt (ln (1 + x))) "(και τα δύο arctan (x) / x και" sqrt (…)

(x + 1) x = (x + 1) x =

# = arctan (x) / (sqrt (x) x sqrt (x ^ -1 ln (1 + x)