Πώς λύνετε ln x ^ 2 = 4;

Πώς λύνετε ln x ^ 2 = 4;
Anonim

Απάντηση:

# x στην {-e ^ 2, e ^ 2} #

Εξήγηση:

# lnx ^ 2 = 4 #

# => x ^ 2 = e ^ 4 #

# => x ^ 2-e ^ 4 = 0 #

Factorize, # => (x-e ^ 2) (x + e ^ 2) = 0 #

Υπάρχουν δύο λύσεις, # => x-e ^ 2 = 0 => x = e ^ 2 #

Και, # => x + e ^ 2 = 0 => x = -e ^ 2 #