Πώς λύνετε ln (x + 1) - lnx = 2;

Απάντηση:

# x = 1 / (e ^ 2-1) #

Εξήγηση:

# n (x + 1) -lnx = 2 #

# n ((x + 1) / x) = ln (e ^ 2) #

#cancel (ln) ((x + 1) / x) = ακύρωση (ln) (e ^ 2) #

# (x + 1) / x = e ^ 2 #

# x + 1 = xe ^ 2 #

# 1 = xe ^ 2 - x #

κοινός παράγοντας

# 1 = x (e ^ 2-1) #

# x = 1 / (e ^ 2-1) #