Εάν f (x) = sin ^ 3x και g (x) = sqrt (3x-1, τι είναι f '(g (x));

# f (x) = sin ^ 3x #, # D_f = RR #

#g (x) = sqrt (3x-1) #, # Dg = 1/3, + oo) #

# D_ (ομίχλη) = {# AAx ##σε##RR: ##Χ##σε## D_g #, # g (x) ##σε## D_f} #

# x> = 1/3 #, #sqrt (3x-1) ##σε## RR # #-># #Χ##σε## 1/3, + oo) #

# AAx ##σε## 1/3, + oo) #,

• ((3x-1)) ((3x-1)) / (2sqrt (3x-1)) # #

# f '(x) = 3sin ^ 2x (sinx)' = 3sin ^ 2xcosx #

Έτσι (3x-1)) cos (sqrt (3x-1)) * 9 / (2sqrt (3x-1)) #