Απάντηση:
(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 4))))) (2 ^ 4 +) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)
Εξήγηση:
(x + 4) / (ln (x ^ 2 + 4)))))) (1))))) (((1) (ln (x ^ 2 + 4)) - (x + 4) (1) / ((x ^ 2 + 4))) ^ 2) #
(x + 4)))))) (ln (x + 4) / (ln (x ^ 2 + 4) (ln (x ^ 2 + 4) - (2x ^ 2 + 4x) / (x ^ 2 + 4))) /
(l) (x + 2) + / (ln (x + 2))))) (x ^ 2 + 4) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)) ^ ακυρώστε (2))) #
(x) = (1 / (ln ((x + 4) / (ln (x ^ 2 4))))) (2 ^ 4 +) (ln (x ^ 2 + 4)) - (2x ^ 2 + 4x)
